Inserimento di righe con modifica

Inserisci righe utilizzando la modifica.

Esempio di codice

C++

Per scoprire come installare e utilizzare la libreria client per Bigtable, consulta Librerie client di Bigtable.

Per eseguire l'autenticazione in Bigtable, configura Credenziali predefinite dell'applicazione. Per maggiori informazioni, consulta Configurare l'autenticazione per un ambiente di sviluppo locale.

namespace cbt = ::google::cloud::bigtable;
[](cbt::Table table) {
  // Write several rows in a single operation, each row has some trivial data.
  cbt::BulkMutation bulk;
  for (int i = 0; i != 5000; ++i) {
    // Note: This example uses sequential numeric IDs for simplicity, but
    // this can result in poor performance in a production application.
    // Since rows are stored in sorted order by key, sequential keys can
    // result in poor distribution of operations across nodes.
    //
    // For more information about how to design a Bigtable schema for the
    // best performance, see the documentation:
    //
    //     https://cloud.google.com/bigtable/docs/schema-design
    char buf[32];
    snprintf(buf, sizeof(buf), "key-%06d", i);
    cbt::SingleRowMutation mutation(buf);
    mutation.emplace_back(
        cbt::SetCell("fam", "col0", "value0-" + std::to_string(i)));
    mutation.emplace_back(
        cbt::SetCell("fam", "col1", "value1-" + std::to_string(i)));
    bulk.emplace_back(std::move(mutation));
  }
  std::vector<cbt::FailedMutation> failures =
      table.BulkApply(std::move(bulk));
  if (failures.empty()) {
    std::cout << "All mutations applied successfully\n";
    return;
  }
  // By default, the `table` object uses the `SafeIdempotentMutationPolicy`
  // which does not retry if any of the mutations fails and are
  // not-idempotent. In this example we simply print such failures, if any,
  // and ignore them otherwise.
  std::cerr << "The following mutations failed and were not retried:\n";
  for (auto const& f : failures) {
    std::cerr << "index[" << f.original_index() << "]=" << f.status() << "\n";
  }
}

Passaggi successivi

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