Agrupar resultados

Demonstra como agrupar descobertas por propriedades

Exemplo de código

Java

static ImmutableList<GroupResult> groupFindings(OrganizationName organizationName) {
  try (SecurityCenterClient client = SecurityCenterClient.create()) {
    // OrganizationName organizationName = OrganizationName.of("123234324");
    SourceName sourceName = SourceName.of(organizationName.getOrganization(), "-");

    GroupFindingsRequest.Builder request =
        GroupFindingsRequest.newBuilder().setParent(sourceName.toString()).setGroupBy("category");

    // Call the API.
    GroupFindingsPagedResponse response = client.groupFindings(request.build());

    // This creates one list for all findings.  If your organization has a large number of
    // findings
    // this can cause out of memory issues.  You can process them batches by returning
    // the Iterable returned response.iterateAll() directly.
    ImmutableList<GroupResult> results = ImmutableList.copyOf(response.iterateAll());
    System.out.println("Findings:");
    System.out.println(results);
    return results;
  } catch (IOException e) {
    throw new RuntimeException("Couldn't create client.", e);
  }
}

Python

from google.cloud import securitycenter

# Create a client.
client = securitycenter.SecurityCenterClient()

# organization_id is the numeric ID of the organization. e.g.:
# organization_id = "111122222444"
org_name = "organizations/{org_id}".format(org_id=organization_id)
# The "sources/-" suffix lists findings across all sources.  You
# also use a specific source_name instead.
all_sources = "{org_name}/sources/-".format(org_name=org_name)
group_result_iterator = client.group_findings(
    request={"parent": all_sources, "group_by": "category"}
)
for i, group_result in enumerate(group_result_iterator):
    print((i + 1), group_result)

A seguir

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