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math.pow
math.pow(base, exponent)
Description
Returns the value of the first arg raised to the power of the second arg. Returns 0 in case of overflow.
Param data types
base: INT|FLOAT
exponent: INT|FLOAT
Return type
FLOAT
Code samples
Example 1
This example shows an integer case.
math.pow(2, 2) // 4.00
Example 2
This example shows a fraction base case.
math.pow(2.200000, 3) // 10.648
Example 3
This example shows a fraction base and power case.
math.pow(2.200000, 1.200000) // 2.575771
Example 4
This example shows a negative power case.
math.pow(3, 0-3) // 0.037037
Example 5
This example shows a fraction power case.
math.pow(3, 0-1.200000) // 0.267581
Example 6
This example shows a negative base case.
math.pow(0-3, 0-3) // -0.037037
Example 7
This example shows a zero base case.
math.pow(0, 3) // 0
Example 8
This example shows a zero power case.
math.pow(9223372036854775807, 0) // 1
Example 9
This example shows a large base case.
math.pow(9223372036854775807, 1.200000) // 57262152889751593549824
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Last updated 2025-07-14 UTC.
[[["Easy to understand","easyToUnderstand","thumb-up"],["Solved my problem","solvedMyProblem","thumb-up"],["Other","otherUp","thumb-up"]],[["Hard to understand","hardToUnderstand","thumb-down"],["Incorrect information or sample code","incorrectInformationOrSampleCode","thumb-down"],["Missing the information/samples I need","missingTheInformationSamplesINeed","thumb-down"],["Other","otherDown","thumb-down"]],["Last updated 2025-07-14 UTC."],[[["\u003cp\u003e\u003ccode\u003emath.pow(base, exponent)\u003c/code\u003e calculates the result of raising the \u003ccode\u003ebase\u003c/code\u003e to the power of the \u003ccode\u003eexponent\u003c/code\u003e.\u003c/p\u003e\n"],["\u003cp\u003eBoth \u003ccode\u003ebase\u003c/code\u003e and \u003ccode\u003eexponent\u003c/code\u003e can be either \u003ccode\u003eINT\u003c/code\u003e or \u003ccode\u003eFLOAT\u003c/code\u003e data types, and the function returns a \u003ccode\u003eFLOAT\u003c/code\u003e value.\u003c/p\u003e\n"],["\u003cp\u003eThe function returns \u003ccode\u003e0\u003c/code\u003e if the operation results in an overflow condition.\u003c/p\u003e\n"],["\u003cp\u003eThe function works with a variety of parameters, such as fractional and negative exponents and negative bases.\u003c/p\u003e\n"],["\u003cp\u003eThe function can also handle cases where the base is zero or the exponent is zero.\u003c/p\u003e\n"]]],[],null,["### math.pow\n\nSupported in: \n[Rules](/chronicle/docs/detection/default-rules) [Search](/chronicle/docs/investigation/udm-search) \n\n math.pow(base, exponent)\n\n#### Description\n\nReturns the value of the first arg raised to the power of the second arg. Returns 0 in case of overflow.\n\n#### Param data types\n\nbase: `INT|FLOAT`\nexponent: `INT|FLOAT`\n\n#### Return type\n\n`FLOAT`\n\n#### Code samples\n\n##### Example 1\n\nThis example shows an integer case. \n\n math.pow(2, 2) // 4.00\n\n##### Example 2\n\nThis example shows a fraction base case. \n\n math.pow(2.200000, 3) // 10.648\n\n##### Example 3\n\nThis example shows a fraction base and power case. \n\n math.pow(2.200000, 1.200000) // 2.575771\n\n##### Example 4\n\nThis example shows a negative power case. \n\n math.pow(3, 0-3) // 0.037037\n\n##### Example 5\n\nThis example shows a fraction power case. \n\n math.pow(3, 0-1.200000) // 0.267581\n\n##### Example 6\n\nThis example shows a negative base case. \n\n math.pow(0-3, 0-3) // -0.037037\n\n##### Example 7\n\nThis example shows a zero base case. \n\n math.pow(0, 3) // 0\n\n##### Example 8\n\nThis example shows a zero power case. \n\n math.pow(9223372036854775807, 0) // 1\n\n##### Example 9\n\nThis example shows a large base case. \n\n math.pow(9223372036854775807, 1.200000) // 57262152889751593549824"]]
