ARRAYCONCAT Function

Combines the elements of one array with another, listing all elements of the first array before listing all elements of the second array.
  • Arrays are referenced by column name or as array literals.
  • This function applies two or more columns of Array type only. To concatenate string values, see Merge Transform.
  • Duplicate values are not removed from the generated array.

Basic Usage

Array literal reference example:

derive type:single value:ARRAYCONCAT([["A","B","C"],["C","D","E"]])

Output: Generates a new column with the following array:

["A","B","C","C","D","E"]

Column reference example:

derive type:single value:ARRAYCONCAT([array1,array2]) as:'concat_Arrays'

Output: Generates a new concat_Arrays column containing a single array listing all of the elements in array1 followed by all elements from array2 in order.

Syntax

derive type:single value:ARRAYCONCAT(array_ref1,array_ref2)

ArgumentRequired?Data TypeDescription
array_ref1Ystring or arrayName of first column or first array literal to apply to the function
array_ref2Ystring or arrayName of second column or second array literal to apply to the function

For more information on syntax standards, see Language Documentation Syntax Notes.

array_ref1, array_ref2

Array literal or name of the array column whose elements you want to concatenate together. You can concatenate together two or more arrays.

Usage Notes:

Required?Data TypeExample Value
YesArray literal or column referencemyArray1, myArray2

Examples

Example - Simple concat example

This simple example illustrates how the following functions operate on nested data.

Source:

Code formatting has been applied to improve legibility.

ItemArrayAArrayB
Item1["A","B","C"]["1","2","3"]
Item2["A","B"]["A","B","C"]
Item3["D","E","F"]["4","5","6"]

Transform:

You can apply the following transforms in the following order. Note that the column names must be different from the transform name, which is a reserved word.

derive type:single value:ARRAYCONCAT([Letters,Numerals]) as:'concat2'

derive type:single value:ARRAYINTERSECT([Letters,Numerals]) as:'intersection2'

derive type:single value:ARRAYCROSS([Letters,Numerals]) as:'cross2'

derive type:single value:ARRAYUNIQUE([Letters,Numerals]) as:'unique2'

Results:

Column set 1:

ItemArrayAArrayBconcat2intersection2
Item1

["A","B","C"]

["1","2","3"]["A","B","C","1","2","3"][ ]
Item2["A","B"]["A","B","C"]["A","B","A","B","C"]["A","B"]
Item3["D","E","F"]["4","5","6"]["D","E","F","4","5","6"][ ]

Column set 2:

Itemcross2unique2
Item1[["A","1"],["A","2"],["A","3"],["B","1"],["B","2"],["B","3"],["C","1"],["C","2"],["C","3"]]["A","B","C","1","2","3"]
Item2[["A","A"],["A","B"],["A","C"],["B","A"],["B","B"],["B","C"]]["A","B","C"]
Item3[["D","4"],["D","5"],["D","6"],["E","4"],["E","5"],["E","6"], ["F","4"],["F","5"],["F","6"]]["D","E","F","4","5","6"]

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